$0.1\mathrm{\hspace{0.33em}}\mathrm{M}$ $\mathrm{K}\mathrm{M}\mathrm{n}{\mathrm{O}}_4$ is used for following titration. What volume of the solution in $\mathrm{mL}$ will be required to react with $0.158\mathrm{\hspace{0.33em}}\mathrm{g}$ of ${\mathrm{N}\mathrm{a}}_2{\mathrm{S}}_2{\mathrm{O}}_3$?
Not balanced: ${\mathrm{S}}_2{\mathrm{O}}_3^{2-}+\mathrm{M}\mathrm{n}{\mathrm{O}}_4^{-}+{\mathrm{H}}_2\mathrm{O}\to \mathrm{M}\mathrm{n}{\mathrm{O}}_{2(\mathrm{s})}+\mathrm{S}{\mathrm{O}}_4^{2-}+\mathrm{O}{\mathrm{H}}^{-}$

• Correct answer
  A

  26.7 mL
• B

  50 mL
• C

  65 mL
• D

  75 mL

Hence, the correct answer is option: 'A'.