Q9 / 54 · NTA Abhyas (JEE Main) 2020 · Chemistry · Redox Reactions

$5 mol$ of $F e_{2} (C_{2} O_{4})_{3}$ is oxidised by $x$ mol of $K_{2} C r_{2} O_{7}$ in acidic medium, calculate the value of $X$ ?

Correct answer: 5

Solution

Eq of

F e_{2} (C_{2} O_{4})_{3}

= eq of

K_{2} C r_{2} O_{7}

5 \times 6 = m o l \times 6

Mol of

K_{2} C r_{2} O_{7}

= 5

Hence, the correct answer is 5.

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