Q49 / 60 · JEE Advanced 2012 (Paper 1) · Physics

Young's double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are $\beta_{G}, \beta_{R}$ and $\beta_{B}$, respectively. Then,

  • A
    $\beta_{G}>\beta_{B}>\beta_{R}$
  • B
    $\beta_{B}>\beta_{G}>\beta_{R}$
  • C
    $\beta_{R}>\beta_{B}>\beta_{G}$
  • Correct answer
    D
    $\beta_{R}>\beta_{G}>\beta_{B}$

Solution

We know that fringe width, $\beta=\frac{\lambda D}{d}$ $\because \quad \lambda_{R}>\lambda_{\mathrm{G}}>\lambda_{B} \quad \therefore \beta_{R}>\beta_{G}>\beta_{B}$

Hence, the correct answer is option: 'D'.

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