Xenon hexafluoride on partial hydrolysis produces compounds 'X' and 'Y' and the respective oxidation states of Xe are:

• A

  ${\mathrm{XeOF}}_2\mathrm{ }(+4)\mathrm{ }\mathrm{and}\mathrm{ }{\mathrm{XeO}}_3\mathrm{ }(+6)$
• B

  ${\mathrm{XeOF}}_4\mathrm{ }\left(+6\right)\mathrm{ }\mathrm{and}\mathrm{ }{\mathrm{XeO}}_3\mathrm{ }(+6)$
• C

  ${\mathrm{XeO}}_2{\mathrm{F}}_2\mathrm{ }(+6)\mathrm{ }\mathrm{and}\mathrm{ }{\mathrm{XeO}}_2\mathrm{ }(+4)$
• Correct answer
  D

  ${\mathrm{XeOF}}_4\mathrm{ }(+6)\mathrm{ }\mathrm{and}\mathrm{ }{\mathrm{XeO}}_2{\mathrm{F}}_2\mathrm{ }(+6)$

Hence, the correct answer is option: 'D'.