Q111 / 160 · TS EAMCET 2019 (03 May Shift 2) · Mathematics

∫x2-1x32x4-2x2+1dx=

  • A
    2x2+2+3x2+c
  • B
    2x2-1x2+2+c
  • C
    2x2+x-2+c
  • Correct answer
    D
    122-2x2+1x4+c

Solution

We have, I=∫x2-1x32x4-2x2+1dx

⇒I=∫x2-1x52-2x-2+x-4dx

⇒I=∫x-3-x-52-2x-2+x-4dx

Put, 2-2x-2+x-4=t⇒2-2x-2+x-4=t2⇒4x-3-4x-5dx=2tdt

⇒I=12∫tdtt

⇒I=t2+c, where c is the constant of integration.

⇒I=122-2x2+1x4+c

Hence, the correct answer is option: 'D'.

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