Q62 / 180 · KCET 2015 · Mathematics

Write the set builder form \( A=\{-1,1\}: \)

  • A
    \( A=\{x: x \) is a real number \( \} \)
  • B
    \( A=\{x: x \) is an integer \( \} \)
  • Correct answer
    C
    \( A=\left\{x: x\right. \) is a root of the equation \( \left.x^{2}=1\right\} \)
  • D
    \( A=\left\{x: x\right. \) is a root of the equation \( \left.x^{2}+1=0\right\} \)

Solution

Given that, $A=-\{1,1\}$ From option $(3), x^{2}=1 \Rightarrow x=\pm 1$ Therefore, $A=\left\{x: x\right.$ is a root of the equation $\left.x^{2}=1\right\}$

Hence, the correct answer is option: 'C'.

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