Q26 / 160 · AP EAMCET 2019 (23 Apr Shift 1) · Chemistry

White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(X\). Chlorine reacts with \(X\) in the presence of wood charcoal to form \(Y . X\) and \(Y\) are respectively

  • Correct answer
    A
    \(\mathrm{SO}_2, \mathrm{SO}_2 \mathrm{Cl}_2\)
  • B
    \(\mathrm{SO}_2, \mathrm{SCl}_4\)
  • C
    \(\mathrm{SO}_3, \mathrm{SO}_2 \mathrm{Cl}_2\)
  • D
    \(\mathrm{SO}_3, \mathrm{SCl}_4\)

Solution

White phosphorus reacts with sulphuryl chloride to form \(\mathrm{PCl}_5\) and \(\mathrm{SO}_2(X)\). Chlorine reacts with \(\mathrm{SO}_2\) in presence of wood charcoal to form \(\mathrm{SO}_2 \mathrm{Cl}_2(Y)\). The reaction can be written as: \(\mathrm{P}_4 \text { (white) }+10 \mathrm{SO}_2 \mathrm{Cl}_2 \longrightarrow 4 \mathrm{PCl}_5+\underset{(X)}{10 \mathrm{SO}_2}\) \(\underset{(X)}{\mathrm{SO}_2}+\mathrm{Cl}_2 \xrightarrow{\text { Wood charcoal }} \mathrm{SO}_2 \underset{(Y)}{\mathrm{Cl}_2}\)

Hence, the correct answer is option: 'A'.

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