Q14 / 90 · JEE Main 2014 (06 Apr) · Chemistry

Which one of the following properties is not shown by NO ?

Correct answer
A
It is diamagnetic in gaseous state
B
It is a neutral oxide
C
It combines with oxygen to form nitrogen dioxide
D
It's bond order is 2.5

Solution

As per MOT, electronic configuration of NO is

σ 1 s^{2} < \overset{*}{σ} 1 s^{2} < σ 2 s^{2} < \overset{*}{σ} 2 s^{2} < σ 2 p_{z}^{2} < π 2 p_{x}^{2} = π 2 p_{y}^{2} < \overset{*}{π} 2 p_{x}^{1} = \overset{*}{π} 2 p_{y}^{0}

It is paramagnetic due to

π 2^{*} {py}^{1}

(unpaired electron)

Bond order of NO

(i . e . O_{_{2}}^{+}) = \frac{10 - 5}{2} = 2.5

Hence, the correct answer is option: 'A'.

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