Q29 / 160 · AP EAMCET 2013 · Chemistry
Which one of the following gives Prussian blue colour?
- A$\mathrm{Fe}_2\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
- B$\mathrm{Na}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]$
- C$\mathrm{Fe}_3\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$
- Correct answerD$\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3$
Solution
Ferric salts (such as $\mathrm{FeCl}_3$ ) form Prussian blue (blue ppt or colouration) with potassium ferrocyanide.
$$
\begin{array}{r}
4 \mathrm{FeCl}_3+3 \mathrm{~K}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right] \longrightarrow \underset{\substack{\text { Prussian blue } \\
\text { (ferric ferrocyanide) }}}{\mathrm{Fe}_4\left[\mathrm{Fe}(\mathrm{CN})_6\right]_3} \\
+12 \mathrm{KCl}
\end{array}
$$
Hence, the correct answer is option: 'D'.