Which one of the following gives a straight line for Freundlich adsorption isotherm?

• Correct answer
  A

  $\log \frac{x}{m} v s \log p$
• B

  $\frac{x}{m} v s \frac{1}{p}$
• C

  $\log \frac{x}{m} v s \log \frac{1}{p}$
• D

  $\frac{x}{m} v s p$

Solution

Freundlich adsorption isotherm is as $\frac{x}{m}=K p^{1 / n}$ Taking logarithms on both sides $\log \frac{x}{m}=\log K+\frac{1}{n} \log p$ On plotting a graph between $\log x / m$ and $\log p$, a straight line will be obtained.

Hence, the correct answer is option: 'A'.