Q30 / 60 · JEE Advanced 2015 (Paper 1) · Mathematics

Which of the following values of α satisfy the equation 1+α21+2α21+3α22+α22+2α22+3α23+α23+2α23+3α2= -648 α ?

  • A
    -4
  • Correct answer
    B
    9
  • Correct answer
    C
    -9
  • D
    4

Solution

1+α21+2α21+3α22+α22+2α22+3α23+α23+2α23+3α2

R2→R2-R1 (Take common)
R3→R3-R1

21+α21+2α21+3α23+2α3+4α3+6α4+2α4+4α4+6α

R3→R3-R2

21+α21+2α21+3α23+2α3+4α3+6α111

C2→C2-C1 (Take common)
C3→C3-C1

∴2α2.α1+α22+3α2+4α3+2α22100

4α2-2α=-8α3=-648α
α=0, α2=81, α=±9

Hence, the correct answer is options: 'B', 'C'.

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