Q17 / 160 · TS EAMCET 2003 · Chemistry

Which of the following reactions proceeds via a secondary free radical?

  • A
    Figure
  • Correct answer
    B
    $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2 \underset{\text { UV light }}{\stackrel{\mathrm{HBr}}{\longrightarrow}}$ $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{Br}$
  • C
    $\mathrm{C}_6 \mathrm{H}_6 \stackrel{\mathrm{Br}_2 / \mathrm{FeBr}_3}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{Br}$
  • D
    $\mathrm{C}_6 \mathrm{H}_6 \underset{\text { UV light }}{\stackrel{\mathrm{Br}_2}{\longrightarrow}} \mathrm{CH}_3-\mathrm{CH}_2 \mathrm{Br}$

Solution

$\mathrm{H}-\mathrm{Br} \stackrel{\mathrm{UV}}{\longrightarrow} \dot{\mathrm{H}}+\mathrm{Br}$. $\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2+\mathrm{B} \dot{\mathrm{r}} \longrightarrow \mathrm{CH}_3-\mathrm{CH}-\mathrm{CH}_2 \mathrm{Br}$ $\mathrm{CH}_3 \mathrm{CH}-\mathrm{CH}_2 \mathrm{Br} \stackrel{\dot{\mathrm{H}}}{\longrightarrow} \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}$

Hence, the correct answer is option: 'B'.

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