Q38 / 160 · AP EAMCET 2006 · Chemistry

Which of the following reactions does no liberate gaseous product ?

Correct answer
A
$\mathrm{AlCl}_3+\mathrm{NaOH} \longrightarrow$
B
$\mathrm{NaOH}+\mathrm{P}$ (white ) $+\mathrm{H}_2 \mathrm{O} \longrightarrow$
C
$\mathrm{Al}+\mathrm{NaOH} \stackrel{\Delta}{\longrightarrow}$
D
$\mathrm{Zn}+\mathrm{NaOH} \stackrel{\Delta}{\longrightarrow}$

Solution

When $\mathrm{AlCl}_3$ reacts with $\mathrm{NaOH}$, it forms sodium meta aluminate $\left(\mathrm{NaAlO}_2\right)$. This reaction does not give gaseous product. $\mathrm{AlCl}_3+4 \mathrm{NaOH} \longrightarrow \mathrm{NaAlO}_2$ (Sod. meta aluminate (soluble)) $+2 \mathrm{H}_2 \mathrm{O}+3 \mathrm{NaCl}$

Hence, the correct answer is option: 'A'.

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