Q2 / 160 · AP EAMCET 2007 · Chemistry

Which of the following pair of transition metal ions, have the same calculated values of magnetic moment?

  • A
    $\mathrm{Ti}^{2+}$ and $\mathrm{V}^{2+}$
  • B
    $\mathrm{Fe}^{2+}$ and $\mathrm{Cu}^{2+}$
  • Correct answer
    C
    $\mathrm{Cr}^{2+}$ and $\mathrm{Fe}^{2+}$
  • D
    $\mathrm{Co}^{2+}$ and $\mathrm{Ti}^{2+}$

Solution

$\mathrm{Cr}^{2+}(Z=24):[\mathrm{Ar}] 3 d^4 4 s^0 ; \quad 4 \quad$ unpaired electrons $\quad \mathrm{Fe}^{2+}(Z=26):[\mathrm{Ar}] 3 d^6 4 s^0$; 4 unpaired electrons $\mathrm{Cr}^{2+}$ and $\mathrm{Fe}^{2+}$ have same number of unpaired electrons, hence they have the same value of magnetic moment.

Hence, the correct answer is option: 'C'.

Relevant Questions