Q55 / 180 · NEET 2015 (Phase 1) · Chemistry

Which of the following options represents the correct bond order?

  • A
    O2->O2>O2+
  • Correct answer
    B
    O2-<O2<O2+
  • C
    O2->O2<O2+
  • D
    O2-<O2>O2+

Solution

B.O=Nb -Na2

O 2 − ⇒σ1 s 2 < σ * 1 s 2 <σ2 s 2 < σ * 2 s 2 <σ2 p z 2 <π2 p x 2 =π2 p y 2 < π * 2 p x 2 = π * 2 p y 1

B.O for O2-=1.5⇒10 - 72=1.5

O 2 ⇒σ1 s 2 < σ * 1 s 2 <σ2 s 2 < σ * 2 s 2 <σ2 p z 2 <π2 p x 2 =π2 p y 2 < π * 2 p x 1 = π * 2 p y 1

B.O for O2=2.0⇒10 - 62=2

O 2 + ⇒σ1 s 2 < σ * 1 s 2 <σ2 s 2 < σ * 2 s 2 <σ2 p z 2 <π2 p x 2 <π2 p y 2 < π * 2 p x 1 < π * 2 p y 0

B.O for O2+=2.5⇒10 - 52=2.5

As per M.O.T electronic configurations

O2-<O2<O2+

Hence, the correct answer is option: 'B'.

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