Q42 / 180 · COMEDK 2021 · Chemistry

Which of the following is most stable?

  • A
    $\mathrm{CH}_{2} \mathrm{~N}_{2}^{+} X^{-}$
  • Correct answer
    B
    $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~N}_{2}^{+} X^{-}$
  • C
    $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{~N}_{2}^{+} X^{-}$
  • D
    $\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{~N}_{2}^{+} X^{-}$

Solution

Stability of diazonium salts ($R-N_2^+X^-$) depends on the stability of the carbocation formed after loss of $N_2$.

$CH_2N_2^+X^-$ and $CH_3CH_2N_2^+X^-$: aliphatic $\Rightarrow$ resulting carbocations are highly unstable. These decompose rapidly.

$C_6H_5CH_2N_2^+X^-$: benzyl carbocation is resonance stabilized, but still relatively reactive.

$C_6H_5N_2^+X^-$: the diazonium group is directly attached to the aromatic ring. The lone pair on the nitrogen delocalizes into the ring $\Rightarrow$ the diazonium cation itself is resonance stabilized. This makes benzene diazonium salt the most stable, existing in solution at $0-5^\circ C$.

Correct option: (2)

Hence, the correct answer is option: 'B'.

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