Which of the following fluorides of xenon is impossible?

• A

  $\mathrm{XeF}_{2}$
• Correct answer
  B

  $\mathrm{XeF}_{3}$
• C

  $\mathrm{XeF}_{4}$
• D

  $\mathrm{XeF}_{6}$

Solution

Xe $\mathrm{F}_{2}:$ Hybridization $\mathrm{sp}^{3} \mathrm{~d}$
Linear Xe $\mathrm{F}_{4}:$ Hybridization $\mathrm{sp}^{3} \mathrm{~d}^{2}$
Square planar $\mathrm{XeF}_{6}:$ Hybribisation $\mathrm{sp}^{3} \mathrm{~d}^{3}$
Pentagonal pyramidal or distorted octahedral

Hence, the correct answer is option: 'B'.