Q70 / 200 · NEET 2009 (Screening) · Chemistry
Which of the following compounds will exhibit cis-trans (geometrical) isomerism?
- Correct answerA2-butene
- BButanol
- C2-butyne
- D2-butenol
Solution
Key Idea Compounds which have at least one double bond $(\mathrm{C}=\mathrm{C})$ and the groups attached with double bonded carbon atoms are different, exhibit geometrical isomerism.
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH} \Rightarrow$ no geometrical isomers butanol $\mathrm{CH}_3 \mathrm{C} \equiv \mathrm{CCH}_3 \Rightarrow$ no geometrical isomers $$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C}(\mathrm{OH})=\mathrm{CH}_2 $$ $\Rightarrow$ no geometrical isomers.
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH} \Rightarrow$ no geometrical isomers butanol $\mathrm{CH}_3 \mathrm{C} \equiv \mathrm{CCH}_3 \Rightarrow$ no geometrical isomers $$ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{C}(\mathrm{OH})=\mathrm{CH}_2 $$ $\Rightarrow$ no geometrical isomers.
Hence, the correct answer is option: 'A'.