Which of the following compounds will exhibit cis-trans (geometrical) isomerism?

• A

  1-Butanol
• Correct answer
  B

  2-Butene
• C

  2-Butanol
• D

  2-Butyne

Solution

$\mathrm{CH}_3 \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_3$ Can exists as
$\Delta \mathrm{G}=\Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}$

Hence, the correct answer is option: 'B'.