Q30 / 150 · MHT CET 2026 (16 April Shift 1) · Chemistry
Which of the following compounds is formed when chlorine reacts with dry slake lime $\text{Ca(OH)}_2$ ?
- Correct answerA$\text{CaOCl}_2$
- B$\text{CaO}_2\text{Cl}_2$
- C$\text{CaOCl}$
- D$\text{CaCl}_2$
Solution
When chlorine gas is passed over dry slaked lime $\text{Ca(OH)}_2$, bleaching powder is formed.
The chemical reaction is given by:
$\text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{CaOCl}_2 + \text{H}_2\text{O}$
The compound formed is $\text{CaOCl}_2$.
Answer: $\text{CaOCl}_2$
The chemical reaction is given by:
$\text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{CaOCl}_2 + \text{H}_2\text{O}$
The compound formed is $\text{CaOCl}_2$.
Answer: $\text{CaOCl}_2$
Hence, the correct answer is option: 'A'.