Q13 / 160 · TS EAMCET 2018 (05 May Shift 2) · Chemistry
Which of the following compounds give basic solution on hydrolysis?
(1) $\mathrm{NH}_4 \mathrm{Cl}$
(2) $\mathrm{K}_2 \mathrm{CO}_3$
(3) $\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}$
(4) $\mathrm{NaCl}$
- A$1,2,3$
- Correct answerB2, 3
- C$2,3,4$
- D3,4
Solution
1. Hydrolysis
$$
\mathrm{NH}_4 \mathrm{Cl}+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{NH}_4 \mathrm{OH}+\mathrm{HCl}
$$
(Weals base) (Strong acid)
So, $\mathrm{NH}_4 \mathrm{Cl}$ is neutral
2. $\mathrm{K}_2 \mathrm{CO}_3+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{KOH}+\mathrm{H}_2 \mathrm{CO}_3$
(Strong base) (Weals acid)
So, basic solution
3. $\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}+7 \mathrm{H}_2 \mathrm{O}$
$$
\longrightarrow 2 \mathrm{NaOH}+4 \mathrm{H}_3 \mathrm{BO}_3+10 \mathrm{H}_2 \mathrm{O}
$$
(Strong base) (Weals acid)
So, is a basic solution.
4. $\mathrm{NaCl}+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{NaOH}+\mathrm{HCl}$
(Strong base) (Strong acid)
So, is a neutral solution.
So, $\mathrm{K}_2 \mathrm{CO}_3$ and $\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7 \cdot 10 \mathrm{H}_2 \mathrm{O}$ gives basic solution.
Hence, the correct answer is option: 'B'.