Which of the following compound has all the four types $\left(1^{\circ}, 2^{\circ}, 3^{\circ}\right.$ and $\left.4^{\circ}\right)$ of carbon atoms?

• A

  2,3,4 -Trimethylpentane
• B

  neo-Pentane
• Correct answer
  C

  2,2,4 -Trimethylpentane
• D

  None of the three

Solution

$\mathrm{C}_{1}$ and $\mathrm{C}_{5}$ are $1^{\circ}, \mathrm{C}_{3}$ is $2^{\circ}, \mathrm{C}_{4}$ is $3^{\circ},$ and $\mathrm{C}_{2}$ is $4^{\circ}$

Hence, the correct answer is option: 'C'.