Q28 / 160 · AP EAMCET 2023 (16 May Shift 2) · Chemistry

Which of the following are not in accordance with the property mentioned against them? I. $\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Oxidising power II. $\mathrm{MI}>\mathrm{MBr}>\mathrm{MCl}>\mathrm{MF}$ : Ionic character of metal halide III. $\mathrm{F}_2>\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{I}_2$ : Bond dissociation enthalpy IV. $\mathrm{HI} < \mathrm{HBr} < \mathrm{HCl} < \mathrm{HF}$ : Hydrogen-halogen bond strength

  • A
    I \& III only
  • Correct answer
    B
    II \& III only
  • C
    I \& IV only
  • D
    II \& IV only

Solution

Ionic character of metal halide :- $\mathrm{M}-\mathrm{F}>\mathrm{M}-\mathrm{Cl}>\mathrm{M}-\mathrm{Br}>\mathrm{M}-\mathrm{I}$ This is due to low polarizability of fluorine due to very small size which gives more ionic character. Thus, II is incorrect. Order of bond dissociation enthalpy :- $\mathrm{Cl}_2>\mathrm{Br}_2>\mathrm{F}_2>\mathrm{I}_2$ This is due to very small size and $\mathrm{F}-\mathrm{F}$ bond length that causes repulsion between the atoms and possible multiple bonds between $\mathrm{Cl}_2, \mathrm{Br}_2$ and $\mathrm{I}_2$ due to availability of $\mathrm{d}$ orbitals. Thus, III is incorrect.

Hence, the correct answer is option: 'B'.

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