Q14 / 180 · COMEDK 2015 · Chemistry
$\mathrm{Pb}_{3} \mathrm{O}_{4}+4 \mathrm{HNO}_{3} \longrightarrow 2 \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{PbO}_{2}$ $+2 \mathrm{H}_{2} \mathrm{O}$
Which is true about the lead ions in $\mathrm{Pb}_{3} \mathrm{O}_{4}$ ?
- Correct answerA$\mathrm{Pb}^{2+}$ reacts with $\mathrm{HNO}_{3}$ to give lead nitrate.
- B$\mathrm{Pb}^{4+}$ reacts with $\mathrm{HNO}_{3}$ to give lead nitrate.
- C$\mathrm{Pb}^{2+}$ reacts with $\mathrm{HNO}_{3}$ to give $\mathrm{PbO}_{2}$.
- D$\mathrm{Pb}^{4+}$ reacts with $\mathrm{HNO}_{3}$ to give $\mathrm{PbO}_{2}$.
Solution
$\mathrm{Pb}_{3} \mathrm{O}_{4}$ is a mixture of $\mathrm{PbO}_{2}+\mathrm{PbO}$ and only $\mathrm{PbO}$ i.e., $\mathrm{Pb}^{2+}$ reacts with $\mathrm{HNO}_{3}$ to form $\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}$.
Hence, the correct answer is option: 'A'.