Q8 / 150 · MHT CET 2026 (18 April Shift 1) · Chemistry

Which from following anions has greater power for coagulation of positive sol?

  • A
    $\text{Cl}^-$
  • Correct answer
    B
    $[\text{Fe(CN)}_6]^{4-}$
  • C
    $\text{PO}_4^{2-}$
  • D
    $\text{SO}_4^{2-}$

Solution

According to the Hardy-Schulze rule, the coagulating power of an ion is directly proportional to the magnitude of its charge (valency). For the coagulation of a positive sol, an anion is required.

The given anions and their charge magnitudes are:
$\text{Cl}^-$ : $1$
$\text{SO}_4^{2-}$ : $2$
$\text{PO}_4^{3-}$ (given as $\text{PO}_4^{2-}$ in options) : $3$
$[\text{Fe(CN)}_6]^{4-}$ : $4$

Since $[\text{Fe(CN)}_6]^{4-}$ has the highest negative charge, it possesses the maximum coagulating power among the given options.

Hence, the correct answer is option: 'B'.

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