Q68 / 90 · JEE Main 2023 (11 Apr Shift 2) · Physics

When vector A→=2i^+3j^+2k^ is subtracted from vector B→, it gives a vector equal to 2j^. Then the magnitude of vector B→ will be:

  • A
    5
  • B
    3
  • C
    6
  • Correct answer
    D
    33

Solution

It is given that A→=2i^+3j^+2k^.

By the given condition,

 B→-(2i^+3j^+2k^)=2j^

 ⇒B→=2i^+5j^+2k^ 

The magnitude is given by the formula,B→=B2x+B2y+B2z
 ⇒|B→|=4+25+4=33           

Hence, the correct answer is option: 'D'.

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