Q121 / 200 · NEET 2004 · Physics
When three identical bulbs of 60 watt, 200 volt rating are connected in series to a 200 volt supply, the power drawn by them will be:
- A60 watt
- B180 watt
- C10 watt
- Correct answerD20 watt
Solution
The resistance of each bulb is $\frac{V^2}{P}$ $=\frac{(200)^2}{60} \Omega$ when three bulbs are connected in series then equivalent resistance is $\frac{3 \bullet(200)^2}{60}$
$\therefore \quad$ Power $P=\frac{V^2}{R_{e q}}=20 \mathrm{~W}$
Hence, the correct answer is option: 'D'.