Q39 / 180 · KCET 2020 · Chemistry

When the same quantity of heat is absorbed by a system at two different temperatures $T_{1}$ and $T_{2}$, such that $T_{1}>T_{2}$, change in entropies are $\Delta S_{1}$ and $\Delta S_{2}$ respectively. Then

  • Correct answer
    A
    $\Delta S_{1} < \Delta S_{2}$
  • B
    $\Delta S_{1}=\Delta S_{2}$
  • C
    $S_{1}>S_{2}$
  • D
    $\Delta S_{2} < \Delta S_{1}$

Solution

We know, $\Delta S=\frac{q_{\mathrm{rev}}}{T}$ Here, $\Delta S_{1}=\frac{q_{\mathrm{rev}}}{T_{1}}$ and $\Delta S_{2}=\frac{q_{\mathrm{rev}}}{T_{2}}$ Here, $q_{\text {rev }}$ is same in both the cases and $T_{1}>T_{2}$ When denominator is larger, the value is lesses. So, $\Delta S_{1} < \Delta S_{2}$

Hence, the correct answer is option: 'A'.

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