Q60 / 180 · COMEDK 2019 · Chemistry
When the same amount of electricity is passed through solutions of silver nitrate and copper sulphate, $0.4 \mathrm{~g}$ copper is deposite(d)The amount of silver deposited is
- Correct answerA$1.35 \mathrm{~g}$
- B$2.7 \mathrm{~g}$
- C$5.1 \mathrm{~g}$
- D$5.4 \mathrm{~g}$
Solution
According to Faraday's second law,
$$
\frac{w_{1}}{E_{1}}=\frac{w_{2}}{E_{2}}
$$
where, $w$ and $E$ are mass and equivalent weight respectively.
$\frac{0.4}{\frac{63.5}{2}}=\frac{w_{2}}{108}$
$\therefore \quad w_{2}=1.35 \mathrm{~g}$
Hence, the correct answer is option: 'A'.