When the roots of $x^3+\alpha x^2+\beta x+6=0$ are increased by 1, if one of the resultant values is the least root of $x^4-6 x^3+11 x^2-6 x=0$, then

• Correct answer
  A

  $\alpha-\beta+5=0$
• B

  $\alpha+\beta+7=0$
• C

  $2 \alpha+\beta+7=0$
• D

  $2 \alpha+3 \beta-1=0$

Hence, the correct answer is option: 'A'.