When the observer moves towards the stationary source with velocity V1, the apparent frequency of the emitted note is F1. When the observer moves away…

Question

When the observer moves towards the stationary source with velocity V1, the apparent frequency of the emitted note is F1. When the observer moves away from the source with velocity V1, the apparent frequency is F2. If V is the velocity of sound in air and F_1/F_2=2 then V/V_1=?

MARKS Content Team · Accepted Answer

Correct answer: (B) 3. F_1/F_2=2 , Speed of approach = Speed of leaving The apparent frequency of sound observed by observer when it is approaching source is given by F_1 =(V+V_1)/V .f_0 ....(i) When observer is moving away from source F_2 =(V−V_1)/V f_0 ....... (ii) Here f_0 is the frequency of sound wave Taking ratio of (i) with (ii) we have F_1/F_2=V/(V-V_1)×(V+V_1)/V=(V+V_1)/(V-V_1) ∴ 2=(V+V_1)/(V-V_1) ∴ 2V-2V_1=V+V_1 ∴ 2V-V=3V_1 ∴ V/V_1=3

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When the observer moves towards the stationary source with velocity V1, the apparent frequency of the emitted note is F1. When the observer moves away from the source with velocity V1, the apparent frequency is F2. If V is the velocity of sound in air and F1F2=2 then VV1=?

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