Q23 / 90 · JEE Main 2022 (25 Jul Shift 2) · Chemistry

When the excited electron of a $H$ atom from $n = 5$ drops to the ground state, the maximum number of emission lines observed are

Correct answer: 10

Solution

Maximum number of emission lines
$= \frac{Δn (Δn + 1)}{2} Δn = n_{2} - n_{1} n_{2} = 5 n_{1} = 1$
Maximum number of emission lines= $\frac{4 (4 + 1)}{2} = \frac{20}{2} = 10$
These lines correspond to the lyman series of the hydrogen spectrum

Hence, the correct answer is 10.

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When the excited electron of a H atom from n=5 drops to the ground state, the maximum number of emission lines observed are

Solution

Relevant Questions

When the excited electron of a $H$ atom from $n = 5$ drops to the ground state, the maximum number of emission lines observed are