Q38 / 111 · NTA Abhyas (NEET) 2020 · Physics · Electromagnetic Induction

When the current in a coil changes from 5 A to 2 A in 0.1 s, an average voltage of 50 V is produced. The self-inductance of the coil is

  • Correct answer
    A
    1.67 H
  • B
    6 H
  • C
    3 H
  • D
    0.67 H

Solution

Magnetic flux

ϕ=LI ⇒ ∆ϕ∆t=L ∆I∆t

∴ εindaverage= ∆ϕ∆t=L ∆I∆t

⇒ 50=L × 5-20.1

⇒  53=L

⇒   L=1.67 H

Hence, the correct answer is option: 'A'.

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