Q82 / 160 · AP EAMCET 2017 (26 Apr Shift 2) · Mathematics
When the coordinate axes are rotated through an angle $\frac{\pi}{4}$ in the positive direction, an equation is transformed to $x^2+y^2-6 x+8 y+21=0$. Then that original equation is
- Correct answerA$x^2+y^2-7 \sqrt{2} x+\sqrt{2} y+21=0$
- B$\sqrt{2} x^2+\sqrt{2} y^2-7 x+y+21 \sqrt{2}=0$
- C$x^2+y^2-14 x+2 y+21=0$
- D$x^2+y^2-7 \sqrt{2} x+\sqrt{2} y+21 \sqrt{2}=0$
Hence, the correct answer is option: 'A'.