Q49 / 180 · KCET 2021 · Chemistry
When the absolute temperature of ideal gas is doubled and pressure is halved, the volume of gas
- Awill be half of original volume
- Correct answerBwill be 4 times the original volume
- Cwill be 2 times the original volume
- Dwill be $1 / 4$ th times the original volume
Solution
Given, final temperature $\left(T_{2}\right)$ $=2 \times\left(T_{1}\right)$ initial temperatue Final pressure $\left(p_{2}\right)=2 \times \frac{\left(p_{1}\right)}{2}$ initial pressure
According to gas law,
$\frac{p_{1} V_{1}}{T_{1}}=\frac{p_{2} V_{2}}{T_{2}}$
$\therefore \quad \frac{p_{1} V_{1}}{T_{1}}=\frac{p_{1} \times V_{2}}{2 \times 2 T_{1}}$
$V_{2}=4 V_{1}$
$\therefore$ Volume increase by 4 times.
Hence, the correct answer is option: 'B'.