Q12 / 160 · TS EAMCET 2008 · Chemistry

When same quantity of electricity is passed through aqueous $\mathrm{AgNO}_3$ and $\mathrm{H}_2 \mathrm{SO}_4$ solutions connected in series, $5.04 \times 10^{-2} \mathrm{~g}$ of $\mathrm{H}_2$ is liberated. What is the mass of silver (in grams) deposited ? (Eq. wts. of hydrogen $=1.008$, silver $=108)$

  • A
    $54$
  • B
    $0.54$
  • Correct answer
    C
    $0.5$
  • D
    $10.8$

Solution

Given, weight of hydrogen liberated $$ =5.04 \times 10^{-2} \mathrm{~g} $$ Eq. wt. of hydrogen $=1.008$ Eq. wt. of silver $=108$ Weight of silver deposited, $w=$ ? According to Faraday's second law of electrolysis weight of silver deposited weight of hydrogen liberated $$ \begin{aligned} & =\frac{\text { eq. wt. of silver }}{\text { eq. wt. of hydrogen }} \\ \frac{w}{5.04 \times 10^{-2}} & =\frac{108}{1.008} \\ w=\frac{108 \times 5.04 \times 10^{-2}}{1.008} & =5.4 \mathrm{~g} \end{aligned} $$

Hence, the correct answer is option: 'C'.

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