Q26 / 110 · VITEEE 2023 · Chemistry

When propionic acid is treated with aqueous \(\mathrm{NaHCO}_3, \mathrm{CO}_2\) is liberated. The \(\mathrm{C}\) of \(\mathrm{CO}_2\) comes from

  • Correct answer
    A
    \(\mathrm{NaHCO}_3\)
  • B
    \(-\mathrm{CH}_3\) group
  • C
    \(-\mathrm{COOH}\) group
  • D
    \(-\mathrm{CH}_2\) group

Solution

Carboxylic acids decompose bicarbonates into \(\mathrm{CO}_2\) gas and \(\mathrm{H}_2 \mathrm{O}\) to form sodium salts of carboxylic acids. So, \(\mathrm{CO}_2\) comes from \(\mathrm{HCO}_3^{-}\)of \(\mathrm{NaHCO}_3\)

Hence, the correct answer is option: 'A'.

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