Q79 / 160 · JIPMER 2014 · Physics

When plate voltage in diode valve is increased from 100 V to 150 V. Then, plate current increases from 7.5 mA to 12 mA, then dynamic plate resistance will be

  • A
    $10 \mathrm{k} \Omega$
  • B
    $11 \mathrm{k} \Omega$
  • C
    $15 \mathrm{k} \Omega$
  • Correct answer
    D
    $11.1 \mathrm{k} \Omega$

Solution

$\begin{aligned} \text { Plate resistance } & =\frac{\Delta V_{P_2}-\Delta V_{P_1}}{\Delta j_{P_2}-\Delta j_R} \\ & =\frac{150-100}{(12-7.5) \times 10^{-3}}=\frac{50 \times 10^3}{4.5}\end{aligned}$ $=11.1 \mathrm{k} \Omega$

Hence, the correct answer is option: 'D'.

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