Q87 / 120 · NEET 2010 (Mains) · Physics

When monochromatic radiation of intensity $I$ falls on a metal surface, the number of photoelectron and their maximum kinetic energy are $N$ and $T$ respectively. If the intensity of radiation is 2I, the number of emitted electrons and their maximum kinetic energy are respectively

  • A
    $\mathrm{N}$ and $2 \mathrm{~T}$
  • Correct answer
    B
    $2 \mathrm{~N}$ and $\mathrm{T}$
  • C
    $2 \mathrm{~N}$ and $2 \mathrm{~T}$
  • D
    $\mathrm{N}$ and $\mathrm{T}$

Solution

(i) Kinetic energy of photoelectrons depends on the frequency of incident radiations and is independent of the intensity of illumination. (ii) Number of photoelectrons depends upon the intensity. So, the number of emitted electrons and their maximum kinetic energy are $2 N$ and $T$ respectively.

Hence, the correct answer is option: 'B'.

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