Q30 / 159 · NTA Abhyas (NEET) 2020 · Chemistry · d and f Block Elements

When MnO42- (1 mole) in neutral aqueous medium is disproportionate, the product obtained is

  • Correct answer
    A
    2/3 mole of MnO4- and 1/3 mole of MnO2
  • B
    1/3 mole of MnO4- and 2/3 mole of MnO2
  • C
    1/3 mole of Mn2O7 and 1/3 mole of MnO2
  • D
    2/3 mole of Mn2O7 and 1/3 mole of MnO2

Solution

3MnO 4 −2  +  4H +  →  2MnO 4 −  +  MnO 2  +  2H 2 O
MnO42- in neutral aqueous medium is disproportionate to 23 mole of MnO4- and 13 mole of MnO2.

Hence, the correct answer is option: 'A'.

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