Q22 / 160 · WBJEE 2012 · Chemistry

When $\mathrm{H}_{2} \mathrm{O}_{2}$ is shaken with an acidified solution of $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ in the presence of ether, the cthereal layer turns blue due to the formation of

  • A
    $\mathrm{Cr}_{2} \mathrm{O}_{3}$
  • B
    $\mathrm{CrO}_{4}^{2-}$
  • C
    $\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}$
  • Correct answer
    D
    $\mathrm{CrO}_{5}$

Solution

$\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{H}_{2} \mathrm{SO}_{4}+4 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow$ $\mathrm{K}_{2} \mathrm{SO}_{4}+5 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{CrO}_{5}$

Hence, the correct answer is option: 'D'.

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