Q47 / 225 · JEE Main 2003 · Chemistry

When $\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH}$ is reduced with $\mathrm{LiAlH}_4$, the compound obtained will be

  • Correct answer
    A
    $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2 \mathrm{OH}$
  • B
    $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{OH}$
  • C
    $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CHO}$
  • D
    $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{COOH}$

Solution

$\mathrm{LiAl}^{\mathrm{H}}{ }_4$ can reduce $\mathrm{COOH}$ group and not the double bond $\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH} \underset{\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}_2 \mathrm{OH}}{\stackrel{\mathrm{LAH}}{\longrightarrow}}$

Hence, the correct answer is option: 'A'.

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