Q17 / 155 · WBJEE 2017 · Chemistry

When $\mathrm{BaCl}_{2}$ is added to an aqueous salt solution, a white precipitate is obtained. The anion among $\mathrm{CO}_{3}^{2-}, \mathrm{SO}_{3}^{2-}$ and $\mathrm{SO}_{4}^{2-}$ that was present in the solution can be

  • A
    $\mathrm{CO}_{3}^{2-}$ but not any of the other two
  • B
    $S O_{3}^{2-}$ but not any of the other two
  • C
    $\mathrm{SO}_{4}^{2-}$ but not any of the other two
  • Correct answer
    D
    Any of them

Solution

$\because$ If $\mathrm{CO}_{3}^{2-}, \mathrm{SO}_{3}^{2-}$ and $\mathrm{SO}_{4}^{2-}$ are present alongwith $\mathrm{BaCl}_{2}$, these can also show white precipitate (as precipitate of all these are also white ).

Hence, the correct answer is option: 'D'.

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