Q17 / 155 · WBJEE 2017 · Chemistry
When $\mathrm{BaCl}_{2}$ is added to an aqueous salt solution, a white precipitate is obtained. The anion among $\mathrm{CO}_{3}^{2-}, \mathrm{SO}_{3}^{2-}$ and $\mathrm{SO}_{4}^{2-}$ that was present in the solution can be
- A$\mathrm{CO}_{3}^{2-}$ but not any of the other two
- B$S O_{3}^{2-}$ but not any of the other two
- C$\mathrm{SO}_{4}^{2-}$ but not any of the other two
- Correct answerDAny of them
Solution
$\because$ If $\mathrm{CO}_{3}^{2-}, \mathrm{SO}_{3}^{2-}$ and $\mathrm{SO}_{4}^{2-}$ are present alongwith $\mathrm{BaCl}_{2}$, these can also show white precipitate (as precipitate of all these are also white ).
Hence, the correct answer is option: 'D'.