Q24 / 111 · NTA Abhyas (NEET) 2020 · Physics · Electromagnetic Induction

When induced emf in inductor coil is 50% of its maximum value then stored energy in inductor coil in the given circuit will be

Figure

  • Correct answer
    A
    2.5 mJ
  • B
    5 mJ
  • C
    15 mJ
  • D
    20 mJ

Solution

If the maximum value of induced EMF is V then 50% of induced EMF is V2. Also, at this moment voltage across resistor will be V2.

E=12Li2

E=12LV2R2

E=125×10-32212

E=2.5 mJ

Hence, the correct answer is option: 'A'.

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