Q42 / 225 · JEE Main 2003 · Chemistry

When during electrolysis of a solution of $\mathrm{AgNO}_3 9650$ coulombs of charge pass through the electroplating bath, the mass of silver deposited on the cathode will be

  • Correct answer
    A
    $10.8 \mathrm{~g}$
  • B
    $21.6 \mathrm{~g}$
  • C
    $108 \mathrm{~g}$
  • D
    $1.08 \mathrm{~g}$

Solution

No. of moles of silver $=\frac{9650}{96500}=\frac{1}{10}$ moles $\therefore$ Mass of silver deposited $=\frac{1}{10} \times 108=10.8 \mathrm{~g}$

Hence, the correct answer is option: 'A'.

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