Q29 / 160 · TS EAMCET 2020 (10 Sep Shift 1) · Chemistry

When copper metal is treated with cold and dilute nitric acid, it forms

  • Correct answer
    A
    $\mathrm{NO}$
  • B
    $\mathrm{N}_2 \mathrm{O}$
  • C
    $\mathrm{N}_2 \mathrm{O}_5$
  • D
    $\mathrm{NO}_3$

Solution

When copper metal is treated with cold and dilute nitric acid. It yields copper nitrate, water and nitric oxide. $3 \mathrm{Cu}+8 \mathrm{HNO}_3($ dil. $) \longrightarrow 3 \mathrm{Cu}\left(\mathrm{NO}_3\right)_2+4 \mathrm{H}_2 \mathrm{O}+2 \mathrm{NO}$

Hence, the correct answer is option: 'A'.

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