When an element ${ }_{90}^{232} \mathrm{Th}$ decays into ${ }_{82}^{208} \mathrm{~Pb}$, the number of $\alpha$ and $\beta^{-}$particles emitted respectively are

• A

  4,8
• B

  8,2
• C

  6,2
• Correct answer
  D

  6,4

Hence, the correct answer is option: 'D'.