Q22 / 90 · JEE Main 2018 (15 Apr) · Chemistry

When an electric current is passed through acidified water, 112 mL of hydrogen gas at N.T.P was collected at the cathode in 965 seconds. The current passed, in ampere, is:

A
2.0
B
0.1
C
0.5
Correct answer
D
1.0

Solution

Cathode
$2 e^{-} + 2 H_{2} O ⟶ H_{2} + 2 O H^{-}$ ${(v . f .)}_{H_{2}} = 2$
Mole $= \frac{i \times t}{v . f . \times 96500}$
$\frac{112}{22400} = \frac{i \times 965}{2 \times 96500}$
$\frac{1}{2} = \frac{i}{2}$
$i = 1 a m p$

Hence, the correct answer is option: 'D'.

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