When a uranium isotope U92235 is bombarded with a neutron, it generates Kr3689, three neutrons and:

Correct answer: (D) Ba56144. Let mass number & atomic number of the unknown element be A & Z. A = 235-89-(3×1)=143 Z = 92-36=56 Hence, the element must be Barium. U92235+01n→Kr3689+Ba56144+301n+Q

Q122 / 180 · NEET 2020 (Phase 1) · Physics

When a uranium isotope ${}_{92}^{235}U$ is bombarded with a neutron, it generates ${}_{36}^{89}{Kr}$ , three neutrons and:

A
${}_{40}^{91}{Zr}$
B
${}_{36}^{101}{Kr}$
C
${}_{36}^{103}{Kr}$
Correct answer
D
${}_{56}^{144}{Ba}$

Solution

Let mass number & atomic number of the unknown element be A & Z.

A = $235 - 89 - (3 \times 1) = 143$

Z = $92 - 36 = 56$

Hence, the element must be Barium.

${}_{92}^{235}U +_{0}^{1} n \to {}_{36}^{89}{Kr} + {}_{56}^{144}{Ba} + 3_{0}^{1} n + Q$

Hence, the correct answer is option: 'D'.

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