Q103 / 150 · MHT CET 2024 (15 May Shift 1) · Physics

When a system is taken from state ' $a$ ' to state ' c ' along a path abc , it is found that $\mathrm{Q}=80 \mathrm{cal}$ and $\mathrm{W}=35 \mathrm{cal}$. Along path adc, $\mathrm{Q}=65 \mathrm{cal}$ the work done W along path adc is Figure

  • Correct answer
    A
    20 cal .
  • B
    45 cal .
  • C
    35 cal .
  • D
    65 cal .

Solution

For both the paths, $\Delta \mathrm{U}$ remains same. For path abc: $\Delta \mathrm{U}=\mathrm{Q}-\mathrm{W}=80-35=45 \mathrm{cal}$ For path adc : $\Delta U=45 \mathrm{cal}$ and $Q=65 \mathrm{cal}$ $\mathrm{W}=\mathrm{Q}-\Delta \mathrm{U}=65-45=20 \mathrm{cal}$

Hence, the correct answer is option: 'A'.

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